Make columns of user and ordergroup lists sortable

This commit implements the sort functionality for the user lists (by name, email, last_activity) and ordergroup lists (by name).
It is a first attempt addressing issue #560.
This commit is contained in:
Harald Reingruber 2022-05-27 17:06:25 +02:00 committed by GitHub
parent 8f94403ccf
commit 0a6345c60b
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14 changed files with 278 additions and 25 deletions

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@ -78,4 +78,122 @@ describe User do
it 'default admin role' do expect(user.role_admin?).to be_truthy end
end
describe 'sort correctly' do
it 'by nick' do
user_b = create :user, nick: 'bbb'
user_a = create :user, nick: 'aaa'
user_c = create :user, nick: 'ccc'
expect(User.sort_by_param('nick')).to eq([user_a, user_b, user_c])
end
it 'reverse by nick' do
user_b = create :user, nick: 'bbb'
user_a = create :user, nick: 'aaa'
user_c = create :user, nick: 'ccc'
expect(User.sort_by_param('nick_reverse')).to eq([user_c, user_b, user_a])
end
it 'by name' do
user_b = create :user, first_name: 'aaa', last_name: 'bbb'
user_a = create :user, first_name: 'aaa', last_name: 'aaa'
user_c = create :user, first_name: 'ccc', last_name: 'aaa'
expect(User.sort_by_param('name')).to eq([user_a, user_b, user_c])
end
it 'reverse by name' do
user_b = create :user, first_name: 'aaa', last_name: 'bbb'
user_a = create :user, first_name: 'aaa', last_name: 'aaa'
user_c = create :user, first_name: 'ccc', last_name: 'aaa'
expect(User.sort_by_param('name_reverse')).to eq([user_c, user_b, user_a])
end
it 'by email' do
user_b = create :user, email: 'bbb@dummy.com'
user_a = create :user, email: 'aaa@dummy.com'
user_c = create :user, email: 'ccc@dummy.com'
expect(User.sort_by_param('email')).to eq([user_a, user_b, user_c])
end
it 'reverse by email' do
user_b = create :user, email: 'bbb@dummy.com'
user_a = create :user, email: 'aaa@dummy.com'
user_c = create :user, email: 'ccc@dummy.com'
expect(User.sort_by_param('email_reverse')).to eq([user_c, user_b, user_a])
end
it 'by phone' do
user_b = create :user, phone: 'bbb'
user_a = create :user, phone: 'aaa'
user_c = create :user, phone: 'ccc'
expect(User.sort_by_param('phone')).to eq([user_a, user_b, user_c])
end
it 'reverse by phone' do
user_b = create :user, phone: 'bbb'
user_a = create :user, phone: 'aaa'
user_c = create :user, phone: 'ccc'
expect(User.sort_by_param('phone_reverse')).to eq([user_c, user_b, user_a])
end
it 'by last_activity' do
user_b = create :user, last_activity: 3.days.ago
user_a = create :user, last_activity: 5.days.ago
user_c = create :user, last_activity: Time.now
expect(User.sort_by_param('last_activity')).to eq([user_a, user_b, user_c])
end
it 'reverse by last_activity' do
user_b = create :user, last_activity: 3.days.ago
user_a = create :user, last_activity: 5.days.ago
user_c = create :user, last_activity: Time.now
expect(User.sort_by_param('last_activity_reverse')).to eq([user_c, user_b, user_a])
end
it 'by ordergroup' do
user_b = create :user, groups: [create(:workgroup, name: 'a'), create(:ordergroup, name: 'bb')]
user_a = create :user, groups: [create(:workgroup, name: 'b'), create(:ordergroup, name: 'aa')]
user_c = create :user, groups: [create(:workgroup, name: 'c'), create(:ordergroup, name: 'cc')]
expect(User.sort_by_param('ordergroup')).to eq([user_a, user_b, user_c])
end
it 'reverse by ordergroup' do
user_b = create :user, groups: [create(:workgroup, name: 'a'), create(:ordergroup, name: 'bb')]
user_a = create :user, groups: [create(:workgroup, name: 'b'), create(:ordergroup, name: 'aa')]
user_c = create :user, groups: [create(:workgroup, name: 'c'), create(:ordergroup, name: 'cc')]
expect(User.sort_by_param('ordergroup_reverse')).to eq([user_c, user_b, user_a])
end
it 'and users are only listed once' do
create :user
expect(User.sort_by_param('ordergroup').size).to eq(1)
end
it 'and users belonging to a workgroup are only listed once' do
create :admin
expect(User.sort_by_param('ordergroup').size).to eq(1)
end
it 'and users belonging to 2 ordergroups are only listed once' do
user = create :user
create :ordergroup, user_ids: [user.id]
create :ordergroup, user_ids: [user.id]
expect(User.sort_by_param('ordergroup').size).to eq(1)
end
end
end